C++ - How Does The Comma Operator Work - Stack Overflow

embedded IAR C/C++ comparsion operator behaviour Stack Overflow

C++ - How Does The Comma Operator Work - Stack Overflow. The way that we can achieve this ordering is that we first compare the first elements, and then we ensure that all the other elements compare the same. However, i'm having trouble switching between the builder types.

Asking for help, clarification, or responding to other answers. In this statement, comma is a separator and tells to the compiler that these (a, b, and c) are three different variables. While declaration multiple variables and providing multiple arguments in a function, comma works as a separator. Comma's effect is to allow a sequence of operations to be performed. Overloaded operator= to switch between template types. Provide details and share your research! In c++, we can overload the comma operator using operator overloading. Class box{ int l, b, h; The comma operator has the lowest precedence of all c/c++ operators. Back them up with references or personal experience.

To learn more, see our tips on writing great. Stack overflow for teams where developers & technologists share private knowledge with coworkers; Essentially, the comma's effect is to cause a sequence of operations to be performed. This means that the expression on the right side will. The comma operator has the lowest precedence of all c/c++ operators. Thanks for contributing an answer to stack overflow! Just trying it wouldn't guarantee portability, and i haven't been able to find an answer, though i fear that it is no, because apparently nobody has even considered it before. The comma operator has the lowest precedence of any c operator, and acts as a sequence point. Making statements based on opinion; So if you have (foo (),bar ()) both functions will be executed, but the value of the expression evaluates to bar (). The problem is that you don't have any friend declaration for the overloaded operator<< and since l, b and h are private they can't be accessed from inside the overloaded operator<<.